3(n-5)^2-4=11(n-5)

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Solution for 3(n-5)^2-4=11(n-5) equation: 



3(n-5)^2-4=11(n-5)

We move all terms to the left:

3(n-5)^2-4-(11(n-5))=0



We calculate terms in parentheses: -(11(n-5)), so:

11(n-5)

We multiply parentheses

11n-55

Back to the equation:

-(11n-55)



We get rid of parentheses

3(n-5)^2-11n+55-4=0

We add all the numbers together, and all the variables

-11n+3(n-5)^2+51=0

We move all terms containing n to the left, all other terms to the right

-11n+3(n-5)^2=-51

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